A small cork with an excess charge of +6.0 µC

is placed 0.25 m from another cork, which
carries a charge of −3.2 µC.
What is the magnitude of the electric force
between the corks? The Coulomb constant is
8.98755 × 10
9
N · m2
/C
2
.
Answer in units of N

F =k•(q1•q2)/r^2 =

=8.98755•10^9•(6•10^-6•3.2•10^-6)/0.25^2=
=2.76 N

How many exes electrons are on the negative cork?

How many electrons has the positive cork lost?

To find the magnitude of the electric force between the two corks, we can use Coulomb's Law:

F = k * |q1 * q2| / r^2

where F is the electric force, k is the Coulomb constant (8.98755 x 10^9 N·m^2/C^2), q1 and q2 are the charges on the corks, and r is the distance between the corks.

Plugging in the values:

q1 = +6.0 µC = 6.0 x 10^-6 C (charge of the first cork)
q2 = -3.2 µC = -3.2 x 10^-6 C (charge of the second cork)
r = 0.25 m (distance between the corks)

F = (8.98755 x 10^9 N·m^2/C^2) * |(6.0 x 10^-6 C) * (-3.2 x 10^-6 C)| / (0.25 m)^2

F = (8.98755 x 10^9 N·m^2/C^2) * (1.92 x 10^-11 C^2) / (0.0625 m^2)

F = 1.44 x 10^-1 N

Therefore, the magnitude of the electric force between the corks is 0.144 N.

To find the magnitude of the electric force between the corks, we can use Coulomb's Law, which states that the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

The formula for Coulomb's Law is:
F = (k * |q1 * q2|) / d^2

where F is the magnitude of the electric force, k is Coulomb's constant (8.98755 × 10^9 N · m^2 / C^2), q1 and q2 are the charges of the two objects, and d is the distance between the objects.

Given:
q1 = +6.0 µC = 6.0 × 10^-6 C
q2 = -3.2 µC = -3.2 × 10^-6 C
d = 0.25 m

Plugging these values into the formula, we have:
F = (8.98755 × 10^9 N · m^2/C^2) * |(6.0 × 10^-6 C) * (-3.2 × 10^-6 C)| / (0.25 m)^2

Now, let's calculate this:

F = (8.98755 × 10^9 N · m^2/C^2) * (6.0 × 10^-6 C * 3.2 × 10^-6 C) / (0.25 m)^2

F = (8.98755 × 10^9 N · m^2/C^2) * (1.92 × 10^-11 C^2) / (0.0625 m^2)

Now, simplify the calculation:

F = 2.87841 N

Therefore, the magnitude of the electric force between the corks is approximately 2.87841 N.