How many moles of Ca(NO3)2 are needed to make 0.250 liters of a 0.200 M Calcium nitrate solution?
To determine how many moles of Ca(NO3)2 are needed to make the solution, we can use the formula:
moles = volume (liters) × concentration (Molarity)
Given:
Volume = 0.250 liters
Concentration = 0.200 M
Plugging in the values into the formula:
moles = 0.250 liters × 0.200 M = 0.050 moles
Therefore, 0.050 moles of Ca(NO3)2 are needed to make 0.250 liters of a 0.200 M Calcium nitrate solution.
How many mols do you need? That is M x L = ?
Then mols = grams/molar mass. You know mols and molar mass, solve for grams. Calcium nitrate is Ca(NO3)2.