Algebra

a farmer wants to enclose a rectangle garden using the sides of her barn as one side of the rectangle. what is the maximum area which she can enclose with 60ft of fence? what should the dimensions of the garden be to give this area?

Max area which she can enclose with 60ft of fence in sq.ft?

dimensions to give area is 30ft by___ft?

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asked by ShelbyA
  1. 2 w + L = 60 so L =60-2w
    A = w L
    A = w (60-2w)
    A = -2w^2+60 w

    2 w^2 -60 w = -A
    w^2 - 30 w = -A/2
    w^2 - 30 w + 225 = -A/2 + 450/2
    (w-15)^2 =-(1/2)(A-450)
    w = 15
    L = 60-30 = 30
    A = 450

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    posted by Damon
  2. If you know any calculus, you can do this much faster
    A = -2w^2+60 w

    dA/dw = 0 at extreme = -4 w + 60
    so w = 60/4 = 15 at max

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    posted by Damon
  3. I can verify that answer as correct

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    posted by Aljaka

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