an object of mass 0.1kg is rotated in a horizontal circle by a string 1m long. the maximum tension in the string before it breaks is 50N.what is its maximum frequency reached?

F = m v^2/r

50 = .1 v^2/1
v^2 = 500
v =10 sqrt 5

circumference = 2 pi r = 2 pi

time around circle = 2 pi /10 sqrt 5

frequency = 1/time = (5/pi) sqrt 5

f = 3.55

0.28s??

are you sure we can use length of the string 1m as the radius? and why?

Your problem statement says the string is one meter long.

hmmm...ok thanks :)

Sry, I misunderstand the question. F=3.55

no the answer is 1.6 revolutions per second

Did you know?

Did you know that the maximum frequency reached by an object being rotated in a horizontal circle is determined by the maximum tension the string can withstand? For instance, if an object with a mass of 0.1kg is rotated by a 1m long string, and the maximum tension the string supports is 50N before breaking, the maximum frequency of rotation can be calculated using the formula: maximum frequency = square root of (maximum tension divided by (2π times mass)). So in this case, the maximum frequency reached can be found by taking the square root of (50N divided by (2π times 0.1kg)), resulting in a value that represents the highest number of complete rotations per unit of time that can be achieved by the object before the string breaks.