Y=3X^2+9X-1
what are the x and y intercepts? Please!
the x intercept is when the line crosses the x axis(y will be zero) and same thing for y(except it crosses the y axis and x = 0)
make for x intercept make y (0=3x^2 + 9x -1) and then factor or use quadratic formula(you can look up the formula if you don't know)
the y intercept is even easier just put zero for x and solve
i mean to say for x intercept make y equal zero (0= 3x^2 +9x-1)
To find the x-intercepts, we set y equal to zero and solve for x:
0 = 3x^2 + 9x - 1
To solve this quadratic equation, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
For our equation, a = 3, b = 9, and c = -1. Plugging these values into the quadratic formula, we get:
x = (-9 ± √(9^2 - 4*3*(-1))) / (2*3)
x = (-9 ± √(81 + 12)) / 6
x = (-9 ± √93) / 6
This gives us two potential x-intercepts:
x = (-9 + √93) / 6 and x = (-9 - √93) / 6
To find the y-intercept, we set x equal to zero and solve for y:
y = 3(0)^2 + 9(0) - 1
y = 0 + 0 - 1
y = -1
Therefore, the y-intercept is -1.
To summarize:
- The x-intercepts are approximately (-9 + √93) / 6 and (-9 - √93) / 6.
- The y-intercept is -1.