12+4+4/3+4/9+..., are needed to yield a sum of 1459/81?
so using the sum formula 12( 1 - (1/3)^n )/(1-1/3) = 1459/81 1 - (1/3)^n = 1459/1458 (1/3)^n = -1/1458 no solution. proof: the sum of the infinite number of terms = a/(1-r) = 12/(1-1/3) = 12(3/2) = 18 and 1459/81 > 18
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