1)Write the equation sin y= x in the form of an inverse function.
A)y=Sin-1x
B)x=Sin-1y
C)y=sin-1x
D)y=Sinx
I chose A
2)Solve y=Arcsin1/2
A)-5pi/6
B)5pi/6
C)-pi/6
D)pi/6
I chose D
3)Find the value of Sin-1(-1/2)
A)-30 degrees
B)30 degrees
C)150 degrees
D)330 degrees
I chose A
4)Find the value of tan(Tan-1 1/2)
A)-1
B)1
C)1/2
D)-1/2
I chose C
ok, except what is the difference between A and C in #1 ?
its just the capital S in A and lowercase s in C
so what's the difference in meaning, I can see the difference in "appearance".
I don't know that's just what it says in my book.
1) To write the equation sin(y) = x in the form of an inverse function, you need to isolate y. This can be done by taking the inverse of the sine function on both sides of the equation.
The inverse of the sine function is denoted as sin^(-1)(x) or arcsin(x). So, to rewrite the equation, we have:
y = sin^(-1)(x)
Among the given options, A) y = Sin^(-1)(x) is the correct answer.
2) To solve the equation y = arcsin(1/2), we want to find the angle whose sine is equal to 1/2.
The value of arcsin(1/2) can be found by taking the inverse sine (or arcsine) of 1/2.
arcsin(1/2) = π/6
Among the given options, D) π/6 is the correct answer.
3) To find the value of sin^(-1)(-1/2), we want to find the angle whose sine is equal to -1/2.
The value of sin^(-1)(-1/2) can be found by taking the inverse sine (or arcsine) of -1/2.
sin^(-1)(-1/2) = -30 degrees
Among the given options, A) -30 degrees is the correct answer.
4) To find the value of tan(tan^(-1)(1/2)), we want to find the tangent of the angle whose tangent is equal to 1/2.
The tangent function and the inverse tangent function (tan and tan^(-1)) are inverse functions of each other. So the value of tan(tan^(-1)(1/2)) is simply 1/2.
Among the given options, C) 1/2 is the correct answer.