The length of a triangle is twice the width. The area is 2yd^2.
Please, find length and width and simplify.
:-)
Do you really mean TRIANGLE?
Yes,yes I do..why
The area of a triangle = 1/2 base times height
A rectangle's area = length times width
May I please see an example of the equation?
http://www.mathsisfun.com/area.html
To find the length and width of the triangle, we'll start by using the formula for the area of a triangle:
Area = (1/2) * length * width.
Given that the area is 2yd², we can set up the equation as follows:
2 = (1/2) * length * width.
We're also given that the length is twice the width, so we can express length as a multiple of the width.
Let's say the width is w.
Then the length will be 2w.
Substituting the values into the equation, we have:
2 = (1/2) * (2w) * w.
Simplifying the equation, we get:
2 = w².
Taking the square root of both sides, we find:
√2 = w.
So the width of the triangle is √2 yards.
To find the length, we substitute the value of the width we just found back into the equation for length:
length = 2w = 2 * √2.
Hence, the length of the triangle is 2√2 yards, and the width is √2 yards.
To summarize:
Length = 2√2 yards
Width = √2 yards
Keep in mind that the answer is simplified, representing the square roots in radical form.