A mass of 0.4113 g of an unknown acid, HA, is titrated with NaOH. If the acid reacts with 28.10 mL of 0.1055 M NaOH, what is the molar mass of the acid?

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  1. mols NaOH = M x L = ?
    Since this is a monoprotic acid, mols NaOH = mols HA.
    mols HA = grams/molar mass
    You know mols and grams, solve for molar mass

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  3. Answer is 138.7 g/mol

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