4^2+6^2=c^2
c^2 = 16 + 36 = 52 = 4*13
so c = 2 sqrt(13)
shouldn't have answer such a basic question for her it feels like she not even trying by posting something this simple
1. 5x + 9 = 3x + 1 2. 14 + 7n = 14n + 28 3. 22(g 1) = 2g + 8
4. d + 12 3d = 5d 6 5. 4(m 2) = 2(3m + 3) 6. (4y 8) = 2(y + 4)
7. 5a 2(4a + 5) = 7a 8. 11w + 2(3w 1) = 15w 9. 4(3 5p) = 5(3p +3)
10. 3(2x + 1) = 2(3x 1) 11. 4(3x + 4) = 2(6x 8) 12. 3n + 3(n + 3) = 3
To solve the equation 4^2 + 6^2 = c^2, you need to calculate the values on both sides of the equation and then find the value of c.
First, let's calculate the values on the left-hand side of the equation:
4^2 = 4 * 4 = 16.
6^2 = 6 * 6 = 36.
So, the left-hand side of the equation becomes: 16 + 36 = 52.
Now, we have the equation 52 = c^2. To find the value of c, we need to take the square root of both sides of the equation. Taking the square root of the right-hand side cancels out the square, leaving us with:
√52 = √(c^2).
The square root of 52 is approximately 7.211.
So, c = 7.211 (rounded to three decimal places).
Therefore, the solution to the equation 4^2 + 6^2 = c^2 is c ≈ 7.211.