4^2+6^2=c^2

c^2 = 16 + 36 = 52 = 4*13

so c = 2 sqrt(13)

shouldn't have answer such a basic question for her it feels like she not even trying by posting something this simple

1. 5x + 9 = 3x + 1 2. 14 + 7n = 14n + 28 3. 22(g  1) = 2g + 8

4. d + 12  3d = 5d  6 5. 4(m  2) = 2(3m + 3) 6.  (4y  8) = 2(y + 4)
7. 5a  2(4a + 5) = 7a 8. 11w + 2(3w  1) = 15w 9. 4(3  5p) = 5(3p +3)
10. 3(2x + 1) = 2(3x  1) 11. 4(3x + 4) = 2(6x  8) 12. 3n + 3(n + 3) = 3

To solve the equation 4^2 + 6^2 = c^2, you need to calculate the values on both sides of the equation and then find the value of c.

First, let's calculate the values on the left-hand side of the equation:

4^2 = 4 * 4 = 16.

6^2 = 6 * 6 = 36.

So, the left-hand side of the equation becomes: 16 + 36 = 52.

Now, we have the equation 52 = c^2. To find the value of c, we need to take the square root of both sides of the equation. Taking the square root of the right-hand side cancels out the square, leaving us with:

√52 = √(c^2).

The square root of 52 is approximately 7.211.

So, c = 7.211 (rounded to three decimal places).

Therefore, the solution to the equation 4^2 + 6^2 = c^2 is c ≈ 7.211.