f(x)= -x^2 + 2x + 15

I search for the coordinates and keep coming up with (-3,5,0) Yes, I am a idiot. Can someone help please?

Maybe. What's the question?

Hi, I am looking for the x coordinates only..f(x)= -x^2 + 2x + 15

how did you get 3 numbers?

i already solve this problem somewhere but ill do it again you can either factor or use quadratic formula (-b plus or minus the square root of b-4AC and all of that divided by 2A)

if you factor ignore the negative on the x^2 multiply the 1 x from x^2 times the 15 to get 15x

the 2 numbers that multiply to get 15 and add up to equal 2( because of the 2x ) is 3 and 5 (i know 3 +5=8 but if one had a negative you would get a 2 but don't put a negative sign because of the negative we left out on the x^2)
and using box technique we get (-x +5, and x + 3; there is a neg in front of the x bc we know we will have negative x^2) put the two equation equal to zero and solve for x, plug back into original eqaution and choose only the answer that is equal to zero(sometimes you will get an answer that doesnt)

Of course! No need to worry, I'm here to help you understand how to find the coordinates of a given function. In this case, you have the function f(x) = -x^2 + 2x + 15 and want to find the coordinates of a point where f(x) equals zero.

To find the x-intercepts (coordinates where the function crosses the x-axis and f(x) equals zero), you need to set the function equal to zero and solve for x. In other words, you're looking for the values of x that make the equation -x^2 + 2x + 15 = 0 true.

To solve this quadratic equation, you can use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a), where a, b, and c are the coefficients of the quadratic equation.

In your case, the coefficients are:
a = -1 (the coefficient of x^2)
b = 2 (the coefficient of x)
c = 15 (the constant term)

Plugging the values into the quadratic formula, we get:
x = (-2 ± √(2^2 - 4(-1)(15))) / (2(-1))
= (-2 ± √(4 + 60)) / (-2)
= (-2 ± √64) / (-2)
= (-2 ± 8) / (-2)

Simplifying further:
For x = (-2 + 8) / (-2) = 6 / (-2) = -3, we have one of the x-intercepts.
For x = (-2 - 8) / (-2) = -10 / (-2) = 5, we have the other x-intercept.

Therefore, the coordinates of the points where f(x) equals zero (x-intercepts) are (-3, 0) and (5, 0). So, (-3, 0) is indeed one of the x-intercepts of the given function.

Keep in mind that if you were searching for the y-coordinate of the point where f(x) equals zero, it would be the value of f(x) when x = -3, which can be found by substituting x = -3 into the function:
f(-3) = -(-3)^2 + 2(-3) + 15
= -9 - 6 + 15
= 0

Therefore, the coordinates of the point on the function where f(x) equals zero are (-3, 0).