a farmer moves along the boundary of a square field of side 10 meter in 40 seconds. what will be the magnitude of displacement of the farmer at the end of 2 minutes and 20 seconds from his initial position?
Perimeter of the field = s = 4•10 =40 m.
v = s/t = 40/40 =1 m/s.
s1 = v•t1 = 1•140 = 140 m =3.5•40 m.
A displacement is the shortest distance from the initial to the final position of a point, therefore, it depends on the initial position of the farmer. If he begins to move from the midpoint of the side, the terminal point will be the midpoint of the opposite side, and the displacement = 10 m. If he begins from the corner, the final point is the opposite corner, therefore, the displacement = 10•sqrt2 =14.1 m.
Cheta
To find the magnitude of displacement of the farmer, we can first calculate the distance the farmer travels in 2 minutes and 20 seconds (140 seconds).
Given that the farmer moves along the boundary of a square field with a side of 10 meters, we can find the total length of the boundary. The boundary consists of four sides, each of length 10 meters. Therefore, the total distance travelled by the farmer in one complete round around the field is 4 * 10 = 40 meters.
Now, we need to find how many complete rounds the farmer makes in 140 seconds. Since the farmer takes 40 seconds to complete one round, we can divide 140 by 40 to find the number of rounds.
140 seconds / 40 seconds/round = 3.5 rounds
So, the farmer makes 3.5 complete rounds in 2 minutes and 20 seconds.
To calculate the distance covered by the farmer, we multiply the number of rounds (3.5) by the distance of one round (40 meters).
Distance covered = 3.5 rounds * 40 meters/round
Distance covered = 140 meters
Therefore, at the end of 2 minutes and 20 seconds, the magnitude of displacement of the farmer from his initial position is 140 meters.