Find the Absolute Value by solving this algebraic-equation?
x-1/3=1/2x+1/6
you just solve it out if its a negative number ignore the sign, 9i e if its negative 3 the absolute value is a 3)
x- 1/3= 1/2x + 1/6 multiply both side by 2 to get;
2x - 2/3 = 1/6 and then plus 2/3 to both side to get;
2x= 5/6 and then divide both side by 2 to get;
x= 5/12
or if your teacher is a real stickler it would be .4167
basically when it ask for absolute value it is asking for how far from zero it is, the reason absolute values never have a negative is becauase there isnt a direction associated with them.
Thank you Visoth I really appreciate your help.
To find the absolute value of an algebraic equation, you need to isolate the absolute value function on one side of the equation. However, the equation you provided does not contain an absolute value function. It is a linear equation.
To solve the equation x - 1/3 = 1/2x + 1/6, we can begin by simplifying the equation.
First, we can eliminate the fractions by multiplying each term by the least common denominator, which is 6. This gives us:
6*(x - 1/3) = 6*(1/2x + 1/6)
6x - 2 = 3x + 1
Next, we can simplify the equation by combining like terms:
6x - 3x = 1 + 2
3x = 3
To isolate the variable x, we divide both sides of the equation by 3:
3x/3 = 3/3
x = 1
Therefore, the solution to the equation x - 1/3 = 1/2x + 1/6 is x = 1.