Ethylene glycol, C2H6O2, is used as antifreeze for automobile engines. If you want to produce 2.00 kg of ethylene glycol from the reaction of C2H4Cl2 and Na2CO3, what is the minimum amount of Na2CO3 that is needed?

C2H4Cl2(l) + Na2CO3(s) + H2O(l)=C2H6O2(l) + 2NaCl(aq) + CO2(g)

mols ethgl = 2000 g/molar mass ethylene glycol.

Convert mols ethylene glycol to mols Na2CO3 with the help of the coefficients in the balanced equation.

Finally, g Na2CO3 = mols x molar mass.

Here is a worked example which follows these steps. Memorize how you do this.
1. Convert g of what you have to mols
2. Convert mols of what you have to mols of what you want.
3. Convert mols of what you want to grams.
http://www.jiskha.com/science/chemistry/stoichiometry.html

2140.96

Well, we all know that ethylene glycol can be a bit of a hot mess, especially when it comes to keeping engines cool. But let's break it down and calculate that minimum amount of Na2CO3 you need.

First things first, we need to find the molar mass of ethylene glycol. So, let's do some math:

C2H6O2:
C = 12.01 g/mol
H = 1.01 g/mol (times 6)
O = 16.00 g/mol (times 2)

Add 'em up:
C2H6O2 = 62.07 g/mol

Now, we need to find the stoichiometry between C2H4Cl2 and Na2CO3. Looking at the balanced equation, we see that 1 mole of C2H4Cl2 reacts with 1 mole of Na2CO3 to produce 1 mole of C2H6O2.

So, based on the molar mass of C2H6O2, we can determine the number of moles required to produce 2.00 kg of ethylene glycol:

2.00 kg = 2000 g
Number of moles = mass/molar mass
Number of moles = 2000 g / 62.07 g/mol

Now, since we know that 1 mole of C2H4Cl2 requires 1 mole of Na2CO3, the minimum amount of Na2CO3 needed is also 2000 g / 62.07 g/mol.

But hey, I'm not all about minimums. If you want to add a little extra Na2CO3 in the mix, just to be on the safe side, go right ahead. Who doesn't love a little extra fizz in their antifreeze, am I right?

To determine the minimum amount of Na2CO3 needed, we need to calculate the stoichiometry of the reaction and compare it to the desired amount of ethylene glycol.

The balanced chemical equation shows that for each mole of C2H4Cl2 reacted, one mole of Na2CO3 is required to produce one mole of ethylene glycol.

Molar mass of C2H4Cl2 = 98.96 g/mol
Molar mass of Na2CO3 = 105.99 g/mol
Molar mass of C2H6O2 = 62.07 g/mol

1 mole of C2H4Cl2 produces 1 mole of Na2CO3, which in turn produces 1 mole of C2H6O2.

To find the minimum amount of Na2CO3 needed, we can use the equation:

Mass of Na2CO3 = (Desired mass of ethylene glycol / Molar mass of C2H6O2) * Molar mass of Na2CO3

Substituting the given values:

Mass of Na2CO3 = (2.00 kg / 62.07 g/mol) * 105.99 g/mol

Converting the mass of ethylene glycol from kg to g:

Mass of Na2CO3 = (2000 g / 62.07 g/mol) * 105.99 g/mol

Calculating the result:

Mass of Na2CO3 = 3399.13 g

Therefore, the minimum amount of Na2CO3 needed to produce 2.00 kg of ethylene glycol is approximately 3399.13 g.

To determine the minimum amount of Na2CO3 needed to produce 2.00 kg of ethylene glycol, we can use stoichiometry and the balanced chemical equation you provided.

From the balanced equation:
1 mole of C2H4Cl2 reacts with 1 mole of Na2CO3 to produce 1 mole of C2H6O2.

First, calculate the molar mass of ethylene glycol (C2H6O2):
Molar mass of C = 12.01 g/mol
Molar mass of H = 1.01 g/mol
Molar mass of O = 16.00 g/mol

Molar mass of C2H6O2 = (2 * 12.01) + (6 * 1.01) + (2 * 16.00) = 62.07 g/mol

Now, calculate the number of moles of ethylene glycol needed:
moles of C2H6O2 = mass / molar mass = 2000 g / 62.07 g/mol = 32.20 mol

Since the stoichiometric ratio between C2H4Cl2 and Na2CO3 is 1:1, we need 32.20 moles of Na2CO3 to react with the 32.20 moles of C2H6O2.

Finally, calculate the minimum amount of Na2CO3 needed:
mass of Na2CO3 = moles of Na2CO3 * molar mass of Na2CO3

The molar mass of Na2CO3 is (2 * 22.99) + 12.01 + (3 * 16.00) = 105.99 g/mol.

mass of Na2CO3 = 32.20 mol * 105.99 g/mol = 3412.50 g

Therefore, the minimum amount of Na2CO3 needed to produce 2.00 kg of ethylene glycol is 3412.50 grams.