According to molecular view, kinetic energy, what happens when 2 tablespoons each of water, methylated spirit and petrol are put in an open container separately in relation to time and the rate of vaporisation?
When two tablespoons of water, methylated spirit, and petrol are put in separate open containers, the rate of vaporization will vary for each substance due to differences in their molecular properties.
Water:
Water molecules have strong hydrogen bonds between them, which require a significant amount of energy to break. As a result, water evaporates at a slower rate compared to other substances in the given scenario. Over time, the water will gradually evaporate, but the rate of vaporization will be relatively slower.
Methylated Spirit:
Methylated spirit consists of a mixture of ethanol and other chemicals. Ethanol has weaker intermolecular forces compared to water, so it evaporates more easily. When placed in an open container, the methylated spirit will begin to evaporate faster than water. As time passes, the liquid level will decrease more rapidly due to the higher rate of vaporization.
Petrol:
Petrol, also known as gasoline, is composed of various hydrocarbons. Hydrocarbons have even weaker intermolecular forces compared to both water and ethanol. Thus, petrol evaporates more readily than water and methylated spirit. When placed in an open container, petrol will have the highest rate of vaporization among the three substances. Consequently, the petrol will evaporate at a considerably faster rate compared to water and methylated spirit, resulting in a more noticeable decrease in the liquid level with time.
In summary, when 2 tablespoons of water, methylated spirit, and petrol are placed in open containers separately, water will evaporate at the slowest rate, followed by methylated spirit, and petrol will have the highest rate of vaporization.