If a standard dot cube is rolled 60 times, how many times woudl you predict that the upturned face will be either 1 or 6?
2/6=x/60 cross multiply gives you 120 = 6x divide by 6 will give you x= 20
2/6=x/60 cross multiply gives you 120 = 6x divide by 6 will give you x= 20
if you want a percentage i think you just take the 20/60 and put it = to x/100% and do the exact same thing
To find the number of times you would predict that the upturned face will be either 1 or 6 when a standard dot cube is rolled 60 times, you need to determine the probability of rolling a 1 or 6 on a single roll and then multiply it by the total number of rolls.
A standard dot cube has 6 sides, numbered from 1 to 6. When rolled, each side has an equal probability of landing face up. Therefore, the probability of rolling a 1 or 6 on a single roll is 2 out of 6, or 1/3.
To find the predicted number of times, multiply the probability by the total number of rolls:
predicted number of times = probability × total number of rolls
predicted number of times = (1/3) × 60
predicted number of times ≈ 20
Therefore, you would predict that the upturned face will be either 1 or 6 approximately 20 times when a standard dot cube is rolled 60 times.
To predict the number of times the upturned face will be either 1 or 6 when a standard dot cube is rolled 60 times, you need to know the probability of rolling a 1 or a 6 on a single roll.
A standard dot cube has six faces, numbered 1 to 6. Each face has an equal chance of landing face up when rolled, so the probability of rolling a 1 or a 6 on a single roll is 2 out of 6, or 1/3.
To find the predicted number of times the upturned face will be either 1 or 6 in 60 rolls, you can use the expected value formula:
Expected Value = Probability × Number of Trials
Expected Value = (1/3) × 60
Expected Value = 20
So, based on probability, we would predict that the upturned face will be either 1 or 6 about 20 times in 60 rolls of the standard dot cube.