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find the stationary points of the following function f(x)=x^3-3x^2-24x-7

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  1. The stationary points are where df/dx = 0
    So solve
    3x^2 -6x -24 = 0
    which is equivalent to
    x^2 -2x - 8 = 0
    (x-4)(x+2) = 0
    That tells you you the two x values where the function is zero.

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