# physics

an object of mass 0.5 kg is whirled at the end of string 0.8 m long if the string make three revolution in 1.2 sec find the tension of the string

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1. tension = sum of centrietal force+gravity
notice these are vectors.

tensionvertical= mg down
= .5*(2PI/.4)^2 * .8

now, after calculating that, you add them as vectors

tension= sqrt ( (mg)^2+(horizonalabove)^2 )

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👨‍🏫
bobpursley
2. 35.6N

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3. I want the nice explanation how the answer came

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