physics

an object of mass 0.5 kg is whirled at the end of string 0.8 m long if the string make three revolution in 1.2 sec find the tension of the string

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  1. tension = sum of centrietal force+gravity
    notice these are vectors.

    tensionvertical= mg down
    tensionhorizonal= m w^2 * rad
    = .5*(2PI/.4)^2 * .8

    now, after calculating that, you add them as vectors

    tension= sqrt ( (mg)^2+(horizonalabove)^2 )

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    bobpursley
  2. 35.6N

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  3. I want the nice explanation how the answer came

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