A mass of 7 kg of water is raised from 8 degrees C to the boiling point 100 degrees C.
How much heat is required? The specific
heat of water is 1000 cal/kg · degrees C.
Answer in units of cal
I got 644000, is that right?
yes.
To calculate the amount of heat required, we can use the formula:
Q = m * c * ΔT
Where:
Q is the amount of heat required (in calories)
m is the mass of the substance (in kg)
c is the specific heat capacity of the substance (in cal/kg · degrees C)
ΔT is the change in temperature (in degrees C)
In this case,
m = 7 kg (given)
c = 1000 cal/kg · degrees C (given)
ΔT = (100 degrees C - 8 degrees C) = 92 degrees C
Plugging these values into the formula, we get:
Q = 7 kg * 1000 cal/kg · degrees C * 92 degrees C
Calculating this, we find:
Q = 644,000 cal
So, your answer of 644,000 cal is correct.