Mr. Rainier's car uses about 1.6 fluid ounces of gas per minute when the engine is idling. One night, he parked his car but forgot to turn off the motor. He had just filled his tank. His tank holds 12 gallons.
About how many hours will it take before his car runs out of gas?
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To determine how many hours it will take before Mr. Rainier's car runs out of gas, we'll need to convert the given information into a common unit of measurement.
First, let's convert the tank capacity from gallons to fluid ounces to match the consumption rate. Since 1 gallon is equivalent to 128 fluid ounces, we can calculate the tank capacity as follows:
12 gallons * 128 fluid ounces/gallon = 1,536 fluid ounces
Now we know that the tank holds 1,536 fluid ounces of gas.
Next, we can calculate the rate of gas consumption per minute. The car consumes 1.6 fluid ounces of gas per minute while idling.
To determine the number of minutes the car will run on a full tank, we divide the tank capacity by the consumption rate:
1,536 fluid ounces / 1.6 fluid ounces/minute = 960 minutes
Finally, let's convert the number of minutes into hours. There are 60 minutes in an hour, so we divide the number of minutes by 60:
960 minutes / 60 minutes/hour = 16 hours
Therefore, it will take approximately 16 hours before Mr. Rainier's car runs out of gas if the engine is left idling.