the heat of fusion of water is 335 J/g. How much heat would be required to melt 97.8 g of ice
97.8 g*335 J/g = ? J.
To determine the amount of heat required to melt 97.8 g of ice, we can use the formula:
Q = m * Hf
where:
Q = heat required (in joules)
m = mass of ice (in grams)
Hf = heat of fusion of water (in J/g)
Substituting the given values into the formula, we have:
Q = 97.8 g * 335 J/g
Now, we can calculate the heat required:
Q = 32793 J
Therefore, it would require approximately 32,793 joules of heat to melt 97.8 grams of ice.