1. Graph y =sec(1/2O-2pi)– 3. the O after the 2 has a slash through it

2. Write an equation for tangent given the period, phase shift, and vertical shift. period = 1/3pi , phase shift = –1/4pi, vertical shift = –5

Post a New Question | Current Questions | Chat With Live Tutors

Homework Help: Calculus. Please!! i need help so bad!!!
Posted by heather on Tuesday, April 24, 2012 at 7:16pm.

1. Graph y =sec(1/2O-2pi)– 3. the O after the 2 has a slash through it

2. Write an equation for tangent given the period, phase shift, and vertical shift. period = 1/3pi , phase shift = –1/4pi, vertical shift = –5
No one has answered this question yet.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Calculus Bonus - There is this bonus that I need so bad for my grade. I have ...
CALCULUS!!! - case 1. Find the absolute maxima and minina values of f(x)=sin2x+...
calculus - A rancher wants to fence in an area of 3000000 square feet in a ...
calculus - I've posted this question before and think I've made some ...
calculus - I've done the first question but I cannot get any farther. I'...

For Further Reading

2. y=tan(30+3/4pi)-5

1. To graph the equation y = sec(1/2O-2pi) - 3, we need to understand the properties of the secant function and how it affects the graph of a function.

The secant function (sec) is the reciprocal of the cosine function (cos). It can be defined as sec(x) = 1/cos(x). The graph of the secant function is periodic, with a period of 2π, meaning it repeats every 2π units. Additionally, the secant function has vertical asymptotes where the cosine function crosses the x-axis.

To graph the given equation, we start by looking at the period. The expression inside the sec function, 1/2O - 2π, indicates the argument of the function. The factor of 1/2 in front of O implies that the period of the secant function will be half of the period of the original O function.

Since the period of O is 2π, the period of the secant function is (1/2)(2π) = π. This means that the graph of y = sec(1/2O-2pi) will repeat every π units.

Next, we observe the vertical shift. The -3 at the end of the equation represents a downward shift of the graph by 3 units.

To plot the graph, we can start by marking the vertical asymptotes at intervals of π. Additionally, we can find a few key points on the graph by evaluating the secant function for specific values of O. For example, when O = π/4, we have y = sec(1/2(π/4) - 2π) - 3. Calculating this value gives us a point on the graph.

By repeating this process and connecting the points, we can plot the graph of the equation y = sec(1/2O-2pi) - 3.

2. To write an equation for the tangent function given the period, phase shift, and vertical shift, we need to understand the formula for the tangent function and how these parameters affect the graph.

The equation for the tangent function (tan) can be written as y = A tan(B(O - C)) + D, where A represents the vertical stretch/compression, B represents the horizontal stretch/compression (period), C represents the phase shift, and D represents the vertical shift.

In this case, the period is given as 1/3π, which means B = 1/(1/3π) = 3π. The phase shift is given as -1/4π, which means C = -(-1/4π) = 1/4π. The vertical shift is given as -5, which means D = -5.

Using these values, we can write the equation for the tangent function. The equation becomes y = A tan(3π(O - 1/4π)) - 5.

In order to determine the value of A, we need additional information like the amplitude. If the amplitude is not specified, we assume it to be 1, which means A = 1.

So, the final equation for the tangent function is y = tan(3π(O - 1/4π)) - 5.