AgCl is often used in silver plating and contains 75.27% Ag by mass. Calculate the mass of AgCl required to plate 155 mg of pure silver?

0.7427 x ? mass AgCl = 0.155 g Ag.

To calculate the mass of AgCl required to plate a given amount of pure silver, we can use the information that AgCl contains 75.27% silver by mass.

Let's assume the mass of AgCl required to plate 155 mg of pure silver is "x grams." Since AgCl contains 75.27% silver by mass, that means the remaining 24.73% is chlorine (Cl).

To calculate the mass of silver in AgCl, we can use the equation:
Mass of Ag = (Percentage of Ag in AgCl / 100) * Mass of AgCl

Given that AgCl contains 75.27% Ag:
Mass of Ag = (75.27 / 100) * x

Since 155 mg of pure silver is being plated, we can equate the mass of silver in AgCl to 155 mg:
(75.27 / 100) * x = 155 mg

To solve for x, we need to convert the units to grams and rearrange the equation:
(75.27 / 100) * x = 155 mg
(75.27 / 100) * x = 0.155 g (since 1 g = 1000 mg)

Now, let's solve for x:
x = (0.155 g) / (75.27 / 100)
x ≈ 0.206 g

Therefore, approximately 0.206 grams of AgCl are required to plate 155 mg of pure silver.