A(n) 0.187 kg baseball is thrown with a speed of 29 m/s. It is hit straight back at the pitcher with a final speed of 22.3 m/s.
What is the magnitude of the impulse delivered to the ball?
Answer in units of kg · m/s
To find the magnitude of the impulse delivered to the ball, you need to use the impulse-momentum principle, which states that the change in momentum of an object is equal to the impulse applied to it.
The momentum of an object is given by the product of its mass and velocity. Since we know the mass of the baseball is 0.187 kg and its initial velocity is 29 m/s, we can calculate its initial momentum:
Initial momentum = mass * initial velocity
Initial momentum = 0.187 kg * 29 m/s
Now, to find the final momentum of the baseball, we need to use its final velocity, which is 22.3 m/s:
Final momentum = mass * final velocity
Final momentum = 0.187 kg * 22.3 m/s
The change in momentum is the difference between the final momentum and the initial momentum:
Change in momentum = Final momentum - Initial momentum
Finally, the magnitude of the impulse delivered to the ball is equal to the absolute value of the change in momentum:
Magnitude of impulse = |Change in momentum|
You can now substitute the values into the equations and calculate the magnitude of the impulse delivered to the ball.