I need help with a C++ exercise.
I need to write a code to display a table consisting of four rows and 11 columns. The first column must contain the numbers 1 through 4 and the other columns must contain the result of multiplying the number in the first column by the numbers 0 through 9. Alignment doesn't matter, and I need to use two "for" statements.
To solve this exercise in C++, you can use nested 'for' loops to create a table with four rows and 11 columns. Here's an example code that accomplishes this:
```cpp
#include <iostream>
int main() {
// Outer loop iterates over the rows
for (int i = 1; i <= 4; i++) {
// Inner loop iterates over the columns
for (int j = 0; j <= 9; j++) {
// Calculate the value for each cell by multiplying the row number with the column number
int value = i * j;
// Display the value
std::cout << value << "\t";
}
// Move to the next line after each row
std::cout << std::endl;
}
return 0;
}
```
Let's break down this code to understand how it works:
1. The outer 'for' loop iterates over the rows, starting from 1 and ending at 4.
2. Inside the outer loop, the inner 'for' loop iterates over the columns, starting from 0 and ending at 9.
3. Inside the inner loop, we calculate the value for each cell by multiplying the current row number (i) with the column number (j).
4. We display the value for each cell using 'cout'.
5. After each row is printed, we move to the next line using 'endl'.
By running this code, you will get a table with four rows and 11 columns, where the first column contains the numbers 1 to 4, and the other columns contain the results of multiplying those numbers by 0 to 9.