Trying to find how many jelly beans that can be in the jar?
Exactly half were red and exactly one-third were blue, which of the following is not a reasonable number of jelly beans that can be in the jar? Is it 24, 50, 60 or 90?
Which of those numbers cannot be divided evenly by 2 and 3?
x in jar
(1/2) x = red
(1/3 )x = blue
total must be divisible by 2 and by 3, or by 6 in other words
50 is not
. There are approximately 9 red jellybeans in a package
for every 4 green jellybeans. Karla opened many packages
of jellybeans and counted a total of 918 red jellybeans.
How many green jellybeans should she expect to find?
To find the number of jelly beans that can be in the jar, we need to consider the given information.
First, we are told that exactly half of the jelly beans in the jar are red. This means that if the total number of jelly beans in the jar is x, then x/2 jelly beans are red.
Next, we are told that exactly one-third of the jelly beans are blue. So, if we let y represent the total number of jelly beans in the jar, we can say that y/3 jelly beans are blue.
To determine which of the given options is not reasonable, we need to evaluate each option by substituting it for y in the equation y/3.
Let's try each option:
1. Option 24:
If y = 24, then 24/3 = 8 jelly beans would be blue. Since we are looking for a number that cannot be the total number of jelly beans, we can eliminate this option.
2. Option 50:
If y = 50, then 50/3 ≈ 16.67 jelly beans would be blue. Since the number of jelly beans must be a whole number, this option is reasonable.
3. Option 60:
If y = 60, then 60/3 = 20 jelly beans would be blue. Since the number of jelly beans must be a whole number, this option is reasonable.
4. Option 90:
If y = 90, then 90/3 = 30 jelly beans would be blue. Since the number of jelly beans must be a whole number, this option is reasonable.
Based on our analysis, the only option that is not reasonable is 24. Therefore, the answer is 24.