A 15mL sodium hydroxide solution of unknown concentration is titrated with 34.5 mL of 1.2M HCl solution. What was the concentration of the sodium hydroxide solution?
2.76 M
To find the concentration of the sodium hydroxide solution, we can use the equation:
M1V1 = M2V2
Where:
M1 = concentration of the sodium hydroxide solution
V1 = volume of the sodium hydroxide solution (15 mL)
M2 = concentration of the HCl solution (1.2 M)
V2 = volume of the HCl solution (34.5 mL)
Rearranging the equation to solve for M1:
M1 = (M2 * V2) / V1
Substituting the values:
M1 = (1.2 M * 34.5 mL) / 15 mL
Calculating:
M1 = 2.76 M
Therefore, the concentration of the sodium hydroxide solution is 2.76 M.
To find the concentration of the sodium hydroxide solution, you can use the concept of stoichiometry and the balanced chemical equation for the reaction between sodium hydroxide (NaOH) and hydrochloric acid (HCl):
NaOH + HCl -> NaCl + H2O
In this reaction, the ratio of moles of NaOH to moles of HCl is 1:1. Therefore, we can set up an equation using the equation:
Mole NaOH / Volume NaOH = Mole HCl / Volume HCl
Let's use the given data to calculate the concentration of the sodium hydroxide solution:
Volume of NaOH solution (V1) = 15 mL
Volume of HCl solution (V2) = 34.5 mL
Concentration of HCl solution (C2) = 1.2 M
First, convert the volumes from mL to L:
V1 = 15 mL = 0.015 L
V2 = 34.5 mL = 0.0345 L
Now substitute the values into the equation:
Mole NaOH / 0.015 L = Mole HCl / 0.0345 L
We know that the moles of HCl can be calculated using its concentration (C2) and volume (V2):
Mole HCl = C2 * V2
Substitute this value into the equation:
Mole NaOH / 0.015 L = (1.2 M * 0.0345 L) / 0.0345 L
Simplifying the equation:
Mole NaOH / 0.015 L = 1.2 M
To calculate the moles of NaOH, multiply the molarity of NaOH by the volume of NaOH:
Mole NaOH = C1 * V1
Let's call C1 the concentration of the NaOH solution.
Substitute this value into the equation:
(C1 * 0.015 L) / 0.015 L = 1.2 M
Simplifying the equation:
C1 = 1.2 M
Therefore, the concentration of the sodium hydroxide solution is 1.2 M.
HCl + NaOH ==> NaCl + H2O
mols HCl = M x L = ?
Use the coefficients to convert mols HCl to mols NaOH.
Then M NaOH = mols NaOH/L NaOH.