CO3 2- +MnO4- ---->??
The balanced chemical equation for the reaction between CO3 2- and MnO4- is as follows:
CO3 2- + 2MnO4- + H2O --> 2MnO2 + CO2 + 2OH-
To balance this equation, start by counting the number of atoms on each side of the equation.
On the left side, we have 1 carbon (C), 3 oxygen (O), 2 manganese (Mn), and 4 oxygen (O).
On the right side, we have 1 carbon (C), 2 oxygen (O), 2 manganese (Mn), 2 oxygen (O), and 2 hydrogen (H).
The number of each atom should be the same on both sides of the equation, so we need to balance the equation accordingly.
To balance the equation, we can start by balancing the number of manganese atoms. We have 2 manganese atoms on the left side and 2 on the right side, which are already balanced.
Next, let's balance the number of carbon atoms. We have 1 carbon atom on both sides, so this is already balanced.
Now, let's balance the number of oxygen atoms. On the left side, we have 3 oxygen atoms from the CO3 2- ion and 4 oxygen atoms from the MnO4- ion. This gives us a total of 7 oxygen atoms on the left side. On the right side, we have 2 oxygen atoms from the CO2 molecule and 2 oxygen atoms from the OH- ion. This gives us a total of 4 oxygen atoms on the right side. To balance the oxygen atoms, we can add water (H2O) to the right side of the equation.
By adding 3 water molecules (H2O) to the right side, we increase the number of oxygen atoms to 10, which balances the equation:
CO3 2- + 2MnO4- + 3H2O --> 2MnO2 + CO2 + 2OH-
So, the balanced chemical equation for the reaction between CO3 2- and MnO4- is:
CO3 2- + 2MnO4- + 3H2O --> 2MnO2 + CO2 + 2OH-