I am still getting the wrong answrs, can you please do me a favor and for each part list the formulas and steps i need to do in order to get the answer. thank you
At serve, a tennis player aims to hit the ball horizontally.
part a)What minimum speed is required for the ball to clear the 0.90m--high net about 15.0m from the server if the ball is "launched" from a height of 2.50m ?
part b)here (relative to server) will the ball land if it just clears the net?
part c)Will it be "good" in the sense that it lands within 7.0m of the net? yes or no ?
part d) How long will it be in the air?
I continued down below, scroll again
Do you agree on the first answer? the horizontal speed?
yeah i got 26.3 because i round it off for the speed
At serve, a tennis player aims to hit the ball horizontally.
part a)What minimum speed is required for the ball to clear the 0.90m--high net about 15.0m from the server if the ball is "launched" from a height of 2.50m ?
part b)here (relative to server) will the ball land if it just clears the net?
part c)Will it be "good" in the sense that it lands within 7.0m of the net? yes or no ?
part d) How long will it be in the air?
======================
u = 26.25 until it hits ground
how long to fall 2.5 m?
2.5 = 4.9 t^2
t =.714 second to hit ground
where will it be?
26.25 * .714 = 18.74 total horizontal dist
18.74 - 15 = 3.74 into opposite side, good shot
time in air was .714 s
thank you, I will calculate everything again and see where I made my mistakes and compare it to these answers. Thanks alot really appreciate it
Sure! I can help you with that. Here are the formulas and steps for each part of the problem:
Part a) To find the minimum speed required to clear the net, we can use the concept of projectile motion. The horizontal distance traveled by the ball can be given by the equation:
Range = (Initial velocity) * (Time of flight)
where Range is the horizontal distance, Initial velocity is the speed at which the ball is launched, and Time of flight is the time the ball stays in the air.
To clear the 0.90m-high net, the height of the ball when it reaches the net must be greater than or equal to 0.9m. We can use the equation for vertical motion to calculate the height of the ball at the net:
Height = (Initial height) + (Initial vertical velocity) * (Time of flight) + (0.5) * (acceleration due to gravity) * (Time of flight)^2
Given that the initial height is 2.50m, the acceleration due to gravity is 9.8 m/s^2, and the height at the net is 0.90m, we can solve for the Initial vertical velocity by setting the above equation equal to 0.90m and rearranging the terms.
Once we have the Initial vertical velocity, we can find the Total initial velocity using the Pythagorean theorem:
Total initial velocity = sqrt((Initial velocity)^2 + (Initial vertical velocity)^2)
So, to summarize the steps:
1. Calculate the Time of flight using the formula: Time of flight = (2 * Total height) / (acceleration due to gravity)
2. Substitute the values in the equation for height to find the Initial vertical velocity.
3. Use the Pythagorean theorem to find the Total initial velocity.
Part b) To find where the ball will land, we need to calculate the horizontal distance traveled by the ball. Using the Range formula mentioned earlier, we can solve for the Time of flight. Then, we can substitute this Time of flight into the equation for horizontal distance to find the landing position.
Part c) To determine if the ball will land within 7.0m of the net, we need to compare the horizontal distance (Range) calculated in Part b) with the 7.0m threshold.
Part d) Once we have the Time of flight from Part a), we can use that value to answer how long the ball will be in the air.
By following these steps and using the appropriate formulas, you should be able to find the answers to each part of the problem.