precalculus
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Trig (Last URGENT)
sin2x+cosx=0 , [180,180) = 2sinxcosx+cosx=0 = cosx(2sinx+1)=0 cosx=0 x1=cos^1(0) x1=90 x2=36090 x2=270 270 doesn't fit in [180,180) what do I do? Or maybe I did something wrong. sinx=1/2 x1=sin^1(1/2) x1=30 x2=18030 x2=150
asked by Anonymous on February 22, 2012 
Trigonometry Check
Simplify #3: [cosxsin(90x)sinx]/[cosxcos(180x)tanx] = [cosx(sin90cosxcos90sinx)sinx]/[cosx(cos180cosx+sinx180sinx)tanx] = [cosx((1)cosx(0)sinx)sinx]/[cosx((1)cosx+(0)sinx)tanx] = [cosxcosxsinx]/[cosx+cosxtanx] =
asked by Anonymous on February 20, 2012 
Math 12
Simplify #1: cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer cscxtanx/sinx+cosx? Simplify #2: sin2x/1+cos2X = ??? I'm stuck on this one. I don't know what I should do.
asked by Anonymous on February 20, 2012 
Trigonometry
Simplify #1: cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer cscxtanx/sinx+cosx? Simplify #2: sin2x/1+cos2X = ??? I'm stuck on this one. I don't know what I should do.
asked by Anonymous on February 20, 2012 
another precal
i have two questions for you to check please! 6cos^2x+5cosx4=0 where 0degrees < or equal to 0 which is < or equal to 360. I got that this factors to (3x+4)(2x1) so the answer is x= 4/3 and x= 1/2 ?? right? and the second
asked by justy on May 14, 2007 
PreCalc
Trigonometric Identities Prove: (tanx + secx 1)/(tanx  secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx + cosx/cosx)/(sinx/cos x  1/cosx + cosx/cosx)= tanx + cosx (just working on the left side) ((sinx + 1 
asked by Dave on January 2, 2007 
Trig........
I need to prove that the following is true. Thanks (cosx / 1sinx ) = ( 1+sinx / cosx ) I recall this question causing all kinds of problems when I was still teaching. it requires a little "trick" L.S. =cosx/(1sinx) multiply top
asked by abdo on April 18, 2007 
precalc
Solve: cos(2x180)  sin(x90)=0 my work: cos2xcos180 + sin2xsin180= sinxcos90  sin90cosx cos2x  sin2x= cosx cos^2x + sin^2x 2sinxcosx=cosx I'm stuck here. I tried subtracting cosx from both sides and making sin^2x into 1
asked by Jess on February 7, 2007 
Math
Verify the identity . (cscXcotX)^2=1cosX/1+cosX _______ sorry i cant help you (cscXcotX)=1/sinX  cosX/sinX = (1cosX)/sinX If you square this you have (1cosX)^2/(sinX)^2 Now use (sinX)^2 = 1  (cosX)^2 to get (1cosX)^2 / 1 
asked by Rose on October 9, 2006 
Precalculus/Trig
I can't seem to prove these trig identities and would really appreciate help: 1. cosx + 1/sin^3x = cscx/1  cosx I changed the 1: cosx/sin^3x + sin^3x/sin^3x = cscx/1cosx Simplified: cosx + sin^3x/sin^3x = cscx/1cosx I don't
asked by Heather on August 15, 2014 
Maths
Solve this equation fo rx in the interval 0
asked by Edward on April 11, 2007