Factor completely.Using the AC method....6x^3-4x^2-10x

1 answer

I don't know what the AC method is but I would do the following:

2x(3x^2-2x-5)
2x(3x-5)(x+1)

Similar Questions

Common factor: 15x^2-10x, 3x^2+24xFactor each polynomial completely: x^2+9x+8, x^2-x-12, x^2+4x-60, x^2-10x+25

Top answer: Common factor: 5x Factors of x^2+9x+8: (x+8)(x+1) Factors of x^2-x-12: (x-4)(x+3) Factors of Read more.
factor each polynomial completely. to begin, state which method should be applied to the first step, given the guidelines of

Top answer: To factor the polynomial completely, you can apply the method of factoring by grouping. Here's how Read more.
Factor completely −5x2 + 10x − 25.−5(x2 − 2x + 5) −1(x2 − 10x + 25) −5x(x2 − 2x + 5) −5(x2 + 2x − 5)

Top answer: −5(x2 − 2x + 5) Read more.
if possibly completely factor the factor the expression(if the polynomial is not factorable using integers enter prime)x^2+10x+1

Top answer: (x+8)(x+2) Read more.
factor this polynomial function completelyf(x)=12x^4+10x^3-214x^2+198x+90 I found all the possible rational zeros but just cant

Top answer: If you found the rational zeros then it is easy to find the factors. e.g. suppose one of the values Read more.
I need some help with a few problems. They are multiple choice but need a breakdown on how I can work the problems. Thanks for

Top answer: 1.10x^2+15x-4x-6 b should be split in such a way that the product is equal to ac and the sum should Read more.
Factor completely -5×2 + 10x - 25.0-5(x2-2x + 5) 0-1(×2 - 10x + 25) 0-5х(×2 - 2x + 5) O-5(x2 + 2x - 5)

Top answer: The correct answer is: -5(x-5)(x+1) Read more.
Factor completely -5×2 + 10x - 25.

Top answer: -5(x^2 - 2x + 5) Read more.
Factor completely -5x^3 + 10x^2

Top answer: -5x^2(x-2) Read more.
Factor the expression completely 16-10x

Top answer: To factor the expression 16-10x completely, we can take out the greatest common factor of the terms, Read more.