A chemist wants to be a supercook and wants to create 8%(m/v) acetic acud solution to be "extra strength" vinegar. if pure acetic acid Is a liquid density of 1.049 g/ml. how many ml of acetic acid should be dissolved to male 500 ml of 8% acetic acid?
It says to first calculate the grams of acetic acid needed bynusing %m/v formula andnthen the next calculation requires you to use the density formula , I'm sure im making it a lot harder than it really is !
mass needed: 500ml*.08, and assuming the 8 percent is the same density as water, then that is 40 grams acetic acid.
volume needed=massneeded/density=40/1.049 ml
So I got 38.13 mL .. Thank you so much now that I see how to do it, it makes much more sense to me.
To solve this problem, we need to follow the two-step process as stated.
Step 1: Calculate the grams of acetic acid needed using the %m/v formula.
The %m/v formula is given by:
%m/v = (grams of solute/volume of solution) x 100
We want to make a 500 ml solution of 8% acetic acid. So, let's calculate the grams of acetic acid required.
Let x be the grams of acetic acid needed.
%m/v = 8%
Volume of solution = 500 ml
8% = (x/500) x 100
8 = (x/500) x 100
8/100 = x/500
0.08 = x/500
Cross-multiplying:
x = 500 x 0.08
x = 40 grams
So, we need 40 grams of acetic acid.
Step 2: Calculate the volume of acetic acid using the density formula.
Density = Mass/Volume
Given:
Density of acetic acid = 1.049 g/ml
Mass of acetic acid = 40 grams
Let y be the volume of acetic acid needed.
1.049 = 40/y
Cross-multiplying:
y = 40/1.049
y ≈ 38.13 ml
Therefore, approximately 38.13 ml of acetic acid should be dissolved to make 500 ml of 8% acetic acid.