Hexane is a hydrocarbon (a molecule containing only carbon and hydrogen) with a molecular weight of 86.18 g/mol,
a density of 0.660 g/mL, and a boiling point of 69C .
Pentanol is an alcohol (a hydrocarbon with a "OH" group attached to one of its carbons) with a molecular weight of
88.15 g/mol, a density of 0.814 g/mL, and a boiling point of 137C .
Calculate the volumes if 4.50 moles of each chemical is present.
Hexane: mL
Pentanol: mL
How is this different than the ones calculated for 3 mols and 4 mols each from yesterday.
please anwser this
To calculate the volumes of each chemical, we need to use their respective densities. The volume can be calculated using the formula:
Volume = Mass / Density
First, let's calculate the mass of each chemical using the given number of moles and molecular weights:
Mass of Hexane = Number of moles of Hexane × Molecular weight of Hexane
Mass of Pentanol = Number of moles of Pentanol × Molecular weight of Pentanol
Now, we can calculate the volumes:
Volume of Hexane = Mass of Hexane / Density of Hexane
Volume of Pentanol = Mass of Pentanol / Density of Pentanol
Given:
Number of moles of Hexane = 4.50 moles
Number of moles of Pentanol = 4.50 moles
Molecular weight of Hexane = 86.18 g/mol
Molecular weight of Pentanol = 88.15 g/mol
Density of Hexane = 0.660 g/mL
Density of Pentanol = 0.814 g/mL
Now, let's calculate the mass of each chemical:
Mass of Hexane = 4.50 moles × 86.18 g/mol
Mass of Hexane = 388.71 g
Mass of Pentanol = 4.50 moles × 88.15 g/mol
Mass of Pentanol = 396.68 g
Finally, let's calculate the volumes:
Volume of Hexane = 388.71 g / 0.660 g/mL
Volume of Hexane = 589.74 mL
Volume of Pentanol = 396.68 g / 0.814 g/mL
Volume of Pentanol = 486.69 mL
Therefore, if 4.50 moles of each chemical is present, the volume of hexane would be 589.74 mL, and the volume of pentanol would be 486.69 mL.