what is the ratio of molezs of NaHCO3 reacted to moles of NaCl produced?

To find the ratio of moles of NaHCO3 reacted to moles of NaCl produced, we need to look at the balanced chemical equation for the reaction between NaHCO3 (sodium bicarbonate) and the production of NaCl (sodium chloride). The balanced chemical equation is:

2 NaHCO3 -> NaCl + H2O + CO2

From the balanced equation, we can see that for every 2 moles of NaHCO3 reacted, we will produce 1 mole of NaCl. Therefore, the ratio of moles of NaHCO3 reacted to moles of NaCl produced is 2:1.

wouldn't it depend on the reaction?