consider the reaction:

N2(g) + O2 (g) --> 2NO (g)

removing some of the N2(g) will_____
A) increase the concentration of O2
B) decrease the concentration of O2
C) increase the concentration of NO(g)

When we do something to a system in equilibrium it will shift one way or the other in order to undo what we've done to it. So if we remove N2 the reaction will shift to try to increase N2. How can it do that? By shifting to the left; in so doing it will decrease concn of NO and increase concn of O2.

Removing some of the N2(g) in the reaction N2(g) + O2(g) --> 2NO(g) will decrease the concentration of N2(g), ultimately leading to a decrease in the concentration of NO(g) as well. Hence, the correct answer is:

B) decrease the concentration of O2

To determine the effect of removing some of the N2(g) on the concentrations of O2 and NO, we need to consider the stoichiometry of the reaction.

The balanced equation for the reaction is as follows:

N2(g) + O2(g) -> 2NO(g)

According to the stoichiometry, one mole of N2 reacts with one mole of O2 to produce two moles of NO.

So, when we remove some of the N2, the reaction will try to compensate for the change by shifting in a direction that will restore the equilibrium.

By removing N2, we are reducing the concentration of N2 in the reaction mixture. As a result, the reaction will shift towards the reactants side to replenish the consumed N2.

Since O2 is a reactant in the reaction, the decrease in N2 concentration will cause a shift towards the reactants. This will increase the concentration of O2 in order to restore the equilibrium. Therefore, the correct answer is:

A) Increase the concentration of O2.