Questions 2-3 refer to : 〖KClO〗_3 + C_6 H_12 O_6 = KCl + 〖CO〗_2 + 〖H〗_2O?
2. Balance the equation.
How many mole of potassium chlorate react with 0.250 mole of glucose
How many grams of carbon dioxide are formed.
How many grams of water are formed.
3. What mass of glucose would have reacted with 8.00g of your 〖KClO〗_3 - NaCl mixture. (remember 8.00g of your mi
Balancing can't be that big a deal? What do you not understand? Same for mols. Just use the coefficients --what about that is giving your trouble?
To balance the chemical equation: 〖KClO〗_3 + C_6 H_12 O_6 = KCl + 〖CO〗_2 + 〖H〗_2O, you will need to make sure that the number of atoms on both sides of the equation is equal.
Here's how to balance the equation:
1. Start by counting the number of each element on each side of the equation.
On the left side:
K: 1
Cl: 1
O: 3
C: 6
H: 12
On the right side:
K: 1
Cl: 1
O: 2
C: 1
H: 2
2. Balance the elements one at a time, starting with the ones that appear in the fewest compounds.
Let's start with potassium (K) and chlorine (Cl). Both are already balanced.
3. Let's balance carbon (C) next. There are 6 carbon atoms on the left side and only 1 on the right side. To balance it, we need to put a coefficient of 6 in front of CO2.
The equation now becomes:
〖KClO〗_3 + C_6 H_12 O_6 = KCl + 6CO2 + 〖H〗_2O
4. Next, balance hydrogen (H). There are 12 hydrogen atoms on the left side and only 2 on the right side. To balance it, we need to put a coefficient of 6 in front of H2O.
The equation now becomes:
〖KClO〗_3 + C_6 H_12 O_6 = KCl + 6CO2 + 6H2O
5. Finally, balance oxygen (O). There are 3 oxygen atoms on the left side and 2 on the right side. To balance it, we need to put a coefficient of 3/2 (which can be written as 1.5) in front of KClO3.
The final balanced equation is:
1.5KClO3 + C6H12O6 = KCl + 6CO2 + 6H2O
Now that the equation is balanced, we can proceed to answer the questions.
2. How many moles of potassium chlorate react with 0.250 moles of glucose?
From the balanced equation, the stoichiometric ratio between potassium chlorate and glucose is 1.5:1. This means that for every 1.5 moles of potassium chlorate, 1 mole of glucose is consumed.
Therefore, if we have 0.250 moles of glucose, we can calculate how many moles of potassium chlorate are needed by multiplying 0.250 moles by the ratio:
Moles of potassium chlorate = 0.250 moles of glucose * (1.5 moles of potassium chlorate / 1 mole of glucose)
The moles of potassium chlorate can then be calculated using simple multiplication.
3. How many grams of carbon dioxide are formed?
From the balanced equation, we can see that the stoichiometric ratio between glucose and CO2 is 1:6. This means that for every 1 mole of glucose, 6 moles of CO2 are produced.
To calculate the grams of CO2 formed, we first need to calculate the moles of glucose using the given mass:
Moles of glucose = mass of glucose / molar mass of glucose
Once we have the moles of glucose, we can convert it to moles of CO2 using the stoichiometric ratio, and then finally convert moles of CO2 to grams using the molar mass of CO2.
The calculation involves three steps: finding moles of glucose, converting those moles to moles of CO2, and then converting moles of CO2 to grams.
4. How many grams of water are formed?
From the balanced equation, we can see that the stoichiometric ratio between glucose and water is 1:6. This means that for every 1 mole of glucose, 6 moles of water are produced.
To calculate the grams of water formed, we can use a similar approach as in the previous question:
Moles of water = moles of glucose * (6 moles of water / 1 mole of glucose)
The moles of water can then be converted to grams using the molar mass of water.
Answer to question 3:
To find the mass of glucose that would have reacted with 8.00g of your KClO3 - NaCl mixture, you need to use the balanced equation and stoichiometry.
First, you need to determine the moles of the KClO3 - NaCl mixture by dividing the given mass by its molar mass. This will give you the number of moles of the mixture.
Next, you can use the stoichiometric ratio between KClO3 and glucose to determine the moles of glucose that would react with the moles of the mixture. This ratio can be obtained from the balanced equation.
Finally, you can convert the moles of glucose to grams by multiplying by the molar mass of glucose.
Remember to substitute the actual molar masses and stoichiometric ratios from the balanced equation into the calculations.