a 2kg and a 4kg hang freely at opposite end of a light in-extensible string which passes over a small and light pulley fixed to a rigid support.calculate the acceleration of the system.

a 2kg and a 4kg hang freely at opposite end of a light in-extensible string which passes over a small and light pulley fixed to a rigid support.calculate the acceleration of the system. a.3.3M/S square b.2.67m/s square c.4.41m/s square d.2.67m/s square.

Option A is the best option

3.3m/s

3.3m/s2

To calculate the acceleration of the system, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.

In this case, we have two masses hanging freely at opposite ends of a light inextensible string. The forces acting on the system are the gravitational forces acting on each mass.

The mass of the first object is 2kg, and the mass of the second object is 4kg. The acceleration of the system is the same for both masses, as they are connected by a string and move together.

First, let's calculate the net force on the system:
- The force acting on the 2kg mass is given by F1 = m1 * g, where m1 is the mass of the 2kg object and g is the acceleration due to gravity.
- The force acting on the 4kg mass is given by F2 = m2 * g, where m2 is the mass of the 4kg object and g is the acceleration due to gravity.
- Since the masses are connected by a string, the tension in the string is the same throughout. Therefore, F1 = F2.

Using Newton's second law, we can write the equation:
m1 * g = m2 * g

Now, let's solve for the acceleration:
Divide both sides of the equation by m1 and m2:
g = g

So, the acceleration of the system is equal to the acceleration due to gravity, which is approximately 9.8 m/s².

Therefore, the acceleration of the system is 9.8 m/s².