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MathReiny
I posted this problem earlier and you answered it for me. The teacher said the correct answer is 3+2y/74y. How is that the answer. Below is what you did earlier 3/(y+2) / (7/y4)) = 3/(y+2) * (y4)/7 = (3y12)/(7y+14) or
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Find X 27^4x2=243^3x+6 Please explain how to do it. Thanks 27^(4x2)=243^(3x+6) Notice that 27 and 243 are both multiples of 3 Changing them.. (3^4)^(4x2)=(3^6)^(3x+6) 3^4(4x2)= 3^6(3x+6) taking the log base 3 of each side.
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Solve each equation by factoring. 7x²243=0 I know I'm supposed to add 243 to the other side but don't know what else to do. Divide maybe? Thanks in advance. 243+7x^2= 0 (reorder) 243+243+7x^2 = 0+243 (add 243 to both sides)
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Whoever you are  Please DO NOT USE TUTORS' NAMES where your name or nickname should be. ~~~~~~~~~~~~~~~~~~~~~~~~~~ as i earlier posted and , 1 day ago , i am confusesd hw we ll find freezing point......isnt it T pure solvent  T
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