Hexane is a hydrocarbon (a molecule containing only carbon and hydrogen) with a molecular weight of 86.18 g/mol,
a density of 0.660 g/mL, and a boiling point of 69C.
Pentanol is an alcohol (a hydrocarbon with a "OH" group attached to one of its carbons) with a molecular weight of
88.15 g/mol, a density of 0.814 g/mL, and a boiling point of 137C.
Calculate the volumes if 4.00 moles of each chemical is present.
Lee, if you will look for a post just a few below this one, you will see the same problem for 3 mols. Just change the numbers.
To calculate the volumes of hexane and pentanol if 4.00 moles of each chemical is present, we can use the information given about their densities. The volume of a substance can be calculated using the formula:
Volume = Mass / Density
First, let's calculate the mass of each chemical. We know the molecular weight, so we can use it to find the mass by multiplying the molecular weight by the number of moles:
Mass = Molecular weight * Moles
For hexane:
Mass of hexane = 86.18 g/mol * 4.00 mol
For pentanol:
Mass of pentanol = 88.15 g/mol * 4.00 mol
Next, we can calculate the volume using the mass and density of each chemical:
Volume of hexane = Mass of hexane / Density of hexane
Volume of pentanol = Mass of pentanol / Density of pentanol
Let's substitute the values:
Volume of hexane = (86.18 g/mol * 4.00 mol) / 0.660 g/mL
Volume of pentanol = (88.15 g/mol * 4.00 mol) / 0.814 g/mL
Now, let's calculate each volume:
Volume of hexane = 52.72 mL
Volume of pentanol = 43.44 mL
Therefore, if 4.00 moles of each chemical is present, the volume of hexane would be 52.72 mL and the volume of pentanol would be 43.44 mL.