Hexane is a hydrocarbon (a molecule containing only carbon and hydrogen) with a molecular weight of 86.18 g/mol,

a density of 0.660 g/mL, and a boiling point of 69C.

Pentanol is an alcohol (a hydrocarbon with a "OH" group attached to one of its carbons) with a molecular weight of
88.15 g/mol, a density of 0.814 g/mL, and a boiling point of 137C.

Calculate the volumes if 3.00 moles of each chemical is present.
Hexane: mL

Pentanol: mL

mass = volume x density

Rearrange to
volume = mass/density

3 mols x molar mass of each = grams of each.
Post your work if you get stuck.

To calculate the volume of a substance, we can use the formula:

Volume (V) = moles (n) / density (d)

Let's calculate the volumes of hexane and pentanol using this formula.

For hexane:
Given: Moles (n) = 3.00 mol, Density (d) = 0.660 g/mL

Step 1: Convert moles to grams using the molecular weight:
Molecular weight of hexane = 86.18 g/mol
Grams (m) = Moles (n) * Molecular weight (M)
m = 3.00 mol * 86.18 g/mol

Step 2: Calculate the volume using the formula:
Volume (V) = Grams (m) / Density (d)
V = m / d

Substituting the values:
V = (3.00 mol * 86.18 g/mol) / 0.660 g/mL

Calculating the result:
V = 386.64 / 0.660 = 586.18 mL

Therefore, the volume of 3.00 moles of hexane is 586.18 mL.

Now, let's calculate the volume of pentanol:
Given: Moles (n) = 3.00 mol, Density (d) = 0.814 g/mL

Step 1: Convert moles to grams using the molecular weight:
Molecular weight of pentanol = 88.15 g/mol
Grams (m) = Moles (n) * Molecular weight (M)
m = 3.00 mol * 88.15 g/mol

Step 2: Calculate the volume using the formula:
Volume (V) = Grams (m) / Density (d)
V = m / d

Substituting the values:
V = (3.00 mol * 88.15 g/mol) / 0.814 g/mL

Calculating the result:
V = 264.45 / 0.814 = 324.43 mL

Therefore, the volume of 3.00 moles of pentanol is 324.43 mL.