gravational force
deimos, a satellite of amrs, has an average radius of 6.3 km. If the gravational force between deimos and a 3.0 kg rock at its surface is 2.5x10(-2)N..what is the mass of deimos ?
Use the Universal Law of gravitation:
Force= G Mm/distance^2 Solve for M.
i did..but how do you solve for the second m ?
can anyone help ?!?!
i would really appreciate some help..anything can help...any physics experts ?
The littlm m is the rock mass, 3 kg. Big M is the mass of the Deimos
so it would be
2.5x10^.2=(6.67x10^-11)(3.0)(M)..divided by 6.3^2
so would the answer be 4.96x10^-15
is this correct?
There is no way that is correct.
m= Force*distance^2 /GM
= 2.5(10^-2)*6300^2 /((6.67x10^-11)*3)
I get almost 5 *10^15 kg
where does 6300 come from
is that 6.3 km=6300 ?
Yes, that's correct! The average radius of Deimos is given as 6.3 km. To use the formula, you need to convert the radius to meters because the units need to be consistent.
1 km = 1000 m
So 6.3 km = 6.3 x 1000 m = 6300 m
Hence, the 6300 comes from converting the given radius of 6.3 km into meters.