An electric power line carries a current of 1600 A in a location where the earth's magnetic field is 4.0*10-5 T. The line makes an angle of 75° with respect to the field. Determine the magnitude of the magnetic force on a 130 m length of line.

F = B i L sin 75

B is the megnetic field in Tesla
i is the current in amperes
L is the length of the wire

To determine the magnitude of the magnetic force on a length of the power line, you can use the equation:

F = I * L * B * sin(θ)

Where:
F = Magnetic force
I = Current (in Amperes)
L = Length of the wire (in meters)
B = Magnetic field strength (in Tesla)
θ = Angle between the wire and the magnetic field (in degrees)

In this case, the given information is:
I = 1600 A
L = 130 m
B = 4.0 * 10^(-5) T
θ = 75°

To solve for the force, substitute the values into the equation:

F = 1600 A * 130 m * 4.0 * 10^(-5) T * sin(75°)

First, convert the angle from degrees to radians:

θ (radians) = θ (degrees) * (π / 180)
θ (radians) = 75° * (π / 180) ≈ 1.309 radians

Substitute the values into the equation and calculate:

F ≈ 1600 A * 130 m * 4.0 * 10^(-5) T * sin(1.309 radians)
F ≈ 53.8 N

Therefore, the magnitude of the magnetic force on a 130 m length of the power line is approximately 53.8 Newtons.