If f(x)= ∫(21,x) t^5 dt then f'(x).
my answer was 1/6 (21^6-x^6) it said it's wrong.
You must be Mily from below.
same thing as before
∫ t^5 dt from t=21 to t=x
= (1/6)t^6 from t-21 to t=x
= (1/6)x^6 - (1/6)(21)^6
= (1/6)(x^6 - 21^6)posted by Reiny
what about f ' (x)?
i did with (1/6)(x^6-21^6) but its wrong
i font know
i got it, it correct answer is f'(x)=-x^5.