college Calculus Help!

If f(x)= ∫(21,x) t^5 dt then f'(x).

my answer was 1/6 (21^6-x^6) it said it's wrong.

asked by LILY
  1. You must be Mily from below.

    same thing as before

    ∫ t^5 dt from t=21 to t=x
    = (1/6)t^6 from t-21 to t=x
    = (1/6)x^6 - (1/6)(21)^6
    = (1/6)(x^6 - 21^6)

    posted by Reiny
  2. what about f ' (x)?
    i did with (1/6)(x^6-21^6) but its wrong

    f(x)=∫(21,x) t^5
    f'(x)= x^5
    i font know

    posted by LILY
  3. but thanks

    posted by LILY
  4. i got it, it correct answer is f'(x)=-x^5.

    posted by LILY

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