college Calculus Help!

If f(x)= ∫(21,x) t^5 dt then f'(x).

my answer was 1/6 (21^6-x^6) it said it's wrong.

asked by LILY
  1. You must be Mily from below.

    same thing as before

    ∫ t^5 dt from t=21 to t=x
    = (1/6)t^6 from t-21 to t=x
    = (1/6)x^6 - (1/6)(21)^6
    = (1/6)(x^6 - 21^6)

    posted by Reiny
  2. what about f ' (x)?
    i did with (1/6)(x^6-21^6) but its wrong

    f(x)=∫(21,x) t^5
    f'(x)= x^5
    i font know

    posted by LILY
  3. but thanks

    posted by LILY
  4. i got it, it correct answer is f'(x)=-x^5.

    posted by LILY

Respond to this Question

First Name

Your Response

Similar Questions

  1. Calculus 2 correction

    I just wanted to see if my answer if correct the integral is: ∫(7x^3 + 2x - 3) / (x^2 + 2) when I do a polynomial division I get: ∫ 7x ((-12x - 3)/(x^2 + 2)) dx so then I use u = x^2 + 2 du = 2x dx 1/2 du = x dx =
  2. Calculus

    Alright, I want to see if I understand the language of these two problems and their solutions. It asks: If F(x) = [given integrand], find the derivative F'(x). So is F(x) just our function, and F'(x) our antiderivative? 1) F(x) =
  3. Calculus- Damon, Steve, Reiny

    I forgot to mention that I am trying to find sigma squared.. given that the mean is r and p(x)= (1/r)(e^(-x/r)) on the interval [0,infinity), where r>0.. note: sigma squared= integral sign (-inf, inf) (x-M)^2 p(x) dx i got (r^2
  4. calculus

    Using an upper-case "C" for any arbitrary constants, find the general indefinite integral ∫ (-2-t)(-9-t^2) dt Now I multiplied both parentheses to get: ∫ (18 + 2t^2 + 9t + t^3) dt now I integrated and got: 18t + 2t^3/3
  5. Calculus III

    Use symmetry to evaluate the double integral ∫∫R(10+x^2⋅y^5) dA, R=[0, 6]×[−4, 4]. (Give your answer as an exact number.) ∫∫R(10+x^2⋅y^5) dA=
  6. Help Evaluating Integrals

    1.) ∫ (2)/(x-4) dx 2.) ∫ sec^2x tanx dx 3.) ∫ 2 csc^2 xdx 4.) ∫ (3) / sqtr(x+3) dx 5.) ∫ (2x-1) / (x^2 - x)

    the fundamental theorem of calculus, f(x)=∫(0,x) t^3+2t^2+ 2 dt, and find f"(x). my answer was: f'(x)=x^3+x^2 f"(x)=3x^2+2x it said its wrong. i don't know how solve with interval, ∫(0,x)
  8. calculus

    Evaluate the integral ∫∫∫2xzdV bounded by Q. Where Q is the region enclosed by the planes x + y + z = 4, y = 3x, x = 0, and z = 0. Answer=16/15 Is this answer correct? cause i've tried doing this problem a bunch
  9. Integral Help

    1.) ∫ (sin x) / (cos^2 x) dx 2.) ∫ (1) / (1+x^2) dx 3.) ∫ xe^x^2 dx 4.) ∫ x^2 sinx dx 5.) ∫ (lnx) / (x) dx
  10. Calculus

    Which of the following integrals represents the volume of the solid formed by revolving the region bounded by y=x^3, y=1, and x=2 about the line y=10? a) pi*∫from (8-1) of (10-y)(2-y^(1/3))dy b) pi*∫ from (1-2) of
  11. Calculus II

    So I'm trying to integrate a function using partial fractions. Here is the integral of interest: ∫(3x^2+5x+3)/[(x+2)(x^2+1)]dx. Since the numerator's degree of the polynomial is lesser than that of the denominator's degree,

More Similar Questions