An experiment calls for 125 mL of 0.105 M NaCl solution. What mass of NaCl is required? What mass of NaCl would be required for 1.00 L of the same solution?
You want how many mols? That is M x L = ?
Then mols = grams/molar mass; solve for grams.
Same process for 1 L
To calculate the mass of NaCl required for a certain volume and concentration of solution, you need to use the formula:
mass = volume × molarity × molar mass
First, let's calculate the mass of NaCl required for 125 mL of 0.105 M NaCl solution.
Step 1: Convert the given volume to liters.
125 mL = 125 mL * (1 L / 1000 mL) = 0.125 L
Step 2: Use the formula to calculate the mass.
mass = 0.125 L × 0.105 M × (mass of NaCl / 1 L)
The molar mass of NaCl is approximately 58.44 g/mol.
mass = 0.125 L × 0.105 mol/L × 58.44 g/mol
mass = 0.771 g
Therefore, for 125 mL of 0.105 M NaCl solution, approximately 0.771 grams of NaCl is required.
Now, let's calculate the mass of NaCl required for 1.00 L of the same solution.
Step 1: Convert the given volume to liters.
1.00 L = 1.00 L
Step 2: Use the formula to calculate the mass.
mass = 1.00 L × 0.105 M × (mass of NaCl / 1 L)
mass = 1.00 L × 0.105 mol/L × 58.44 g/mol
mass = 6.14 g
Therefore, for 1.00 L of the same 0.105 M NaCl solution, approximately 6.14 grams of NaCl is required.