A 125-g piece of metal is heated to 288 degrees celsius and dropped into 85.0 g of water at 26 degrees celsius. If the final temperature of water and metal is 58 degrees celsius, what is the specific heat of the metal?

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  1. heat lost by metal + heat gained by water = 0
    [mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
    Substitute the numbers and solve for the only unknown, the specific heat of the metal.

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  2. 0.38J|g○C

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  3. 700

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  4. 9.76g

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  5. 0.129 J/g C

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