What is the x-coordinate of the image of P(5,11) under R-0,90*-?
To find the x-coordinate of the image point, we need to rotate the given point P(5, 11) counterclockwise by 90 degrees around the origin (0, 0).
To accomplish this, we can use the formula for a 90-degree counterclockwise rotation for a point (x, y) by substituting the given values:
x' = x * cos(θ) - y * sin(θ)
y' = x * sin(θ) + y * cos(θ)
Let's calculate the x-coordinate of the image point:
x' = 5 * cos(90°) - 11 * sin(90°)
= 5 * 0 - 11 * 1
= 0 - 11
= -11
Therefore, the x-coordinate of the image of P(5,11) under a counterclockwise rotation of 90 degrees is -11.