Balance each of the following equations
a)CH4+CL2......>CCl4+HCl
b)AL(OH)3+H2SO4.....>Al2(SO4)3+H2O
c)Fe+H2O......>fe3O4+H2
d)Al4C3+HCl......>AlCl3+CH4
e)C2H6+O2......>CO2+H2O
f)P2H4.......>PH3+P4
g)S2Cl2+NH3......>N4S4+NH4CL+S8
h)Ag+HNO3.......>AgNO3+NO+H2O
a) CH4 + 4Cl2 → CCl4 + 4HCl
b) 2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O
c) 3Fe + 4H2O → Fe3O4 + 4H2
d) Al4C3 + 12HCl → 4AlCl3 + 3CH4
e) 2C2H6 + 7O2 → 4CO2 + 6H2O
f) 4P2H4 → 8PH3 + P4
g) 4S2Cl2 + 16NH3 → N4S4 + 8NH4Cl + 3S8
h) 3Ag + 3HNO3 → 3AgNO3 + NO + 2H2O
To balance each of the given equations, we need to make sure that the number of atoms of each element is the same on both sides of the equation. Let's balance each equation step-by-step:
a) CH4 + Cl2 → CCl4 + HCl
We have 1 Carbon (C) atom on the left side and 1 on the right side, so they are balanced.
We have 4 Hydrogen (H) atoms on the left side and 1 on the right side, so we need to multiply HCl by 4 to balance the Hydrogen.
We have 2 Chlorine (Cl) atoms on the left side and 4 on the right side, so we need to multiply Cl2 by 2 to balance the Chlorine.
The balanced equation is: CH4 + 2Cl2 → CCl4 + 4HCl
b) Al(OH)3 + H2SO4 → Al2(SO4)3 + H2O
We have 2 Aluminum (Al) atoms on the left side and 2 on the right side, so they are balanced.
We have 6 Hydrogen (H) atoms on the left side and 6 on the right side, so they are balanced.
We have 6 Oxygen (O) atoms on the left side and 6 on the right side, so they are balanced.
We have 3 Sulfur (S) atoms on the right side and none on the left side, so we need to multiply H2SO4 by 3 to balance the Sulfur.
The balanced equation is: Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 3H2O
c) Fe + H2O → Fe3O4 + H2
We have 1 Iron (Fe) atom on the left side and 3 on the right side, so we need to multiply Fe by 3 to balance the Iron.
We have 2 Oxygen (O) atoms on the left side and 4 on the right side, so we need to multiply H2O by 2 to balance the Oxygen.
The balanced equation is: 3Fe + 4H2O → Fe3O4 + 4H2
d) Al4C3 + HCl → AlCl3 + CH4
We have 4 Aluminum (Al) atoms on the left side and 1 on the right side, so we need to multiply AlCl3 by 4 to balance the Aluminum.
We have 3 Carbon (C) atoms on the left side and 4 on the right side, so we need to multiply Al4C3 by 3 to balance the Carbon.
We have 3 Chlorine (Cl) atoms on the right side and only 1 on the left side, so we need to multiply HCl by 3 to balance the Chlorine.
The balanced equation is: 4Al4C3 + 3HCl → 12AlCl3 + CH4
e) C2H6 + O2 → CO2 + H2O
We have 2 Carbon (C) atoms on the left side and 1 on the right side, so we need to multiply CO2 by 2 to balance the Carbon.
We have 6 Hydrogen (H) atoms on the left side and 2 on the right side, so we need to multiply H2O by 3 to balance the Hydrogen.
We have 2 Oxygen (O) atoms on the left side and 7 on the right side, so we need to multiply O2 by 7/2 (3.5) to balance the Oxygen.
Since we cannot have fractional coefficients, we can multiply the entire equation by 2 to get whole number coefficients.
The balanced equation is: 2C2H6 + 7O2 → 4CO2 + 6H2O
f) P2H4 → PH3 + P4
We have 2 Phosphorus (P) atoms on the left side and 4 on the right side, so we need to multiply P2H4 by 2 to balance the Phosphorus.
We have 4 Hydrogen (H) atoms on the left side and 3 on the right side, so we need to multiply PH3 by 2 to balance the Hydrogen.
The balanced equation is: 2P2H4 → 4PH3 + P4
g) S2Cl2 + NH3 → N4S4 + NH4Cl + S8
We have 2 Sulfur (S) atoms on the left side and 8 on the right side, so we need to multiply S8 by 2 to balance the Sulfur.
The balanced equation is: S2Cl2 + NH3 → N4S4 + NH4Cl + 2S8
h) Ag + HNO3 → AgNO3 + NO + H2O
We have 1 Silver (Ag) atom on the left side and 1 on the right side, so they are balanced.
We have 1 Nitrogen (N) atom on the right side and none on the left side, so we need to multiply HNO3 by 2 to balance the Nitrogen.
We have 3 Oxygen (O) atoms on the right side and only 1 on the left side, so we need to multiply HNO3 by 3 to balance the Oxygen.
The balanced equation is: Ag + 2HNO3 → AgNO3 + NO + H2O