When the following solutions are mixed together, FeSO4 (aq) + Csl (aq):
What is the balanced equation?
What is the complete ionic equation? What is the net ionic equation?
I don't know how to balance these problems, can someone please show me how to solve this?
I answered this below. These two materials do not react. There is no equation to balance.Both FeSO4 and CsI are soluble. You can show those dissolving in water and dissociating into Fe(II) ions and sulfate ions along with Cs ions and I ions but that's all you can do and this isn't what is called a net ionic equation.
To balance a chemical equation, you need to ensure that the number and type of atoms on both sides of the equation are the same. Here's how you can solve it step by step:
1. Write the given reactants and products:
FeSO4 (aq) + CsI (aq) →
2. Identify the elements present in each compound:
FeSO4 contains Fe, S, and O.
CsI contains Cs and I.
3. Balance the equation by starting with the most complex molecule and adjusting the coefficients:
The number of Cs atoms is balanced by putting a coefficient of 2 in front of CsI:
FeSO4 (aq) + 2CsI (aq) →
4. Next, balance the number of I atoms by putting a coefficient of 2 in front of FeSO4:
FeSO4 (aq) + 2CsI (aq) → 2FeI (aq) + Cs2SO4 (aq)
Now that we have the balanced equation, let's move on to the complete ionic equation and the net ionic equation.
Complete ionic equation:
The complete ionic equation shows all the ions present in the reaction, including the spectator ions.
FeSO4 (aq) + 2CsI (aq) → 2FeI (aq) + Cs2SO4 (aq)
Breaking the aqueous compounds into their respective ions:
Fe2+ (aq) + SO4 2- (aq) + 2Cs+ (aq) + 2I- (aq) → 2FeI (aq) + Cs2SO4 (aq)
Net ionic equation:
The net ionic equation is obtained by removing the spectator ions, which are ions that appear on both sides of the reaction and do not participate in the actual chemical reaction.
Fe2+ (aq) + 2I- (aq) → 2FeI (aq)
In this case, Cs+ and SO4 2- are the spectator ions.
By following these steps, you can balance an equation and obtain the complete ionic equation and net ionic equation.