C = 2nr!?!??!??!

Since the NYS Math Exam is coming up (in my district in my school we have it next week). You see in my class were not done with our geometry and ratio, proportion unit and plus we are missing one unit: algebra. We didn't get to solving the formulas. Ratio and proportion I think were done with that unit idk.... Over the spring break we are required to do this workbook (ALL OF IT). I'm almost done with it though.
Algebra I learn a lot I guess bcuz she assign us pages in our work book and I usually do the problems with my mom. Anyways there is this geometry problem about C = 2nr. I don't remember how to solve this in order. Can you teach me how to solve C = 2nr please or is there a website that shows step-by-step on how to solve it plus with an example.

Thank You! :)

I think you mean:

Circumference = 2 * pi * radius

http://www.mathsisfun.com/geometry/circle.html

Yes.

Thank You! :)

You're welcome. Good luck on your exam!

Thanks

BTW - I checked on my school website my math exam is after the ELA so next week is the ELA .... oops lol :) I thought the math was next week.

Sure! I can help you understand how to solve the equation C = 2nr. This equation represents the circumference (C) of a circle, which is equal to twice the product of the radius (r) and the constant pi (π), often approximated as 3.14159.

To solve C = 2nr, you need to rearrange the equation to solve for a specific variable. Let's go step by step:

Step 1: Start with the equation C = 2nr.

Step 2: Divide both sides of the equation by 2n to isolate the variable r. This gives us C/(2n) = r.

Step 3: Simplify the expression C/(2n) to get the value of r.

So, if you have values for C and n, you can find the value of r by dividing C by 2n.

For example, let's say you have a circle with a circumference of 20 units and a value of n equal to 3. Substitute these values into the equation:

r = C/(2n)
r = 20 / (2 * 3) [substituting C = 20 and n = 3]
r = 20 / 6
r = 3.33 units (rounded to two decimal places)

Therefore, the radius of the circle in this example would be approximately 3.33 units.

If you want further practice or would like to see more examples, there are several math websites and resources available online. Khan Academy, for instance, provides step-by-step explanations and examples for various math topics, including solving equations involving circles. You can visit their website (https://www.khanacademy.org) and search for the specific topic or equation you are interested in.