The heat ofvaporization of water at 373K is40.7kj/mol. Find q for the evaporation of 491g of water at this temperation
q = mass water x heat vap.
I would convert 491g H2O to mols by dividing by 18 g/mol.
1098.9
To find the value of q for the evaporation of 491g of water at a temperature of 373K, we can make use of the equation q = m * ΔHvap, where q is the heat involved in the process, m is the mass of the substance being evaporated, and ΔHvap is the heat of vaporization.
In this case, the mass of water, m, is given as 491g. However, to make this calculation easier, we should convert the mass into moles. The molar mass of water (H2O) is approximately 18 g/mol.
To find the number of moles (n), we can use the equation:
n = m / M
where n is the number of moles, m is the mass, and M is the molar mass.
Substituting the given values:
n = 491g / 18 g/mol
n = 27.28 mol (rounded to two decimal places)
Now, we can calculate the value of q using the equation q = m * ΔHvap:
q = n * ΔHvap
q = 27.28 mol * 40.7 kJ/mol
Calculating this out will give us the value of q for the evaporation of 491g of water at 373K.